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=1/2Y^2-6
We move all terms to the left:
-(1/2Y^2-6)=0
Domain of the equation: 2Y^2-6)!=0We get rid of parentheses
Y∈R
-1/2Y^2+6=0
We multiply all the terms by the denominator
6*2Y^2-1=0
Wy multiply elements
12Y^2-1=0
a = 12; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·12·(-1)
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*12}=\frac{0-4\sqrt{3}}{24} =-\frac{4\sqrt{3}}{24} =-\frac{\sqrt{3}}{6} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*12}=\frac{0+4\sqrt{3}}{24} =\frac{4\sqrt{3}}{24} =\frac{\sqrt{3}}{6} $
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